A 50.0 mL sample containing Cd2 and Mn2 was treated with 58.7 mL of 0.0500 M EDTA. Titration of the excess unreacted EDTA required 17.7 mL of 0.0300 M Ca2 . The Cd2 was displaced from EDTA by the addition of an excess of CN–. Titration of the newly freed EDTA required 29.1 mL of 0.0300 M Ca2 . What were the molarities of Cd2 and Mn2 in the original solution?

1 answer

0999