friction force=pushing force
mu(mg+250SinTheta)=250cosTheta
solve for mu
A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an angle of 26.0° below the horizontal is applied to the box. What is the minimum coefficient of static friction between the box and the surface required for the box to remain stationary?
1) 0.441 2) 0.654 3) 0.375 4) 0.866 5) 0.406
2 answers
0.441