Q=Q₁+Q₂+Q₃=
=mc(ice)(27-0)+mλ(ice) +mc(water) (35-0)=
=5(2060•27 + 335000 + 4183•35) = …
A 5-kg block of ice is at a temperature of -27 °C. How much heat must be added to the
ice to produce 5 kg of liquid water with a final temperature of 35 oC?
2 answers
By the way, ice and water have different specific heat capacities. That is what was tripping me up.