Asked by Anonymous
A 5-digit PIN code cannot begin with zero and the remaining digits have no restrictions. If repetition of digits is allowed, then what is the probability that the PIN code begins with a 7 and ends with an 8?
Answers
Answered by
Reiny
number of possible codes
= 9x10x10x10x10 = 90000
number starting with 7 and ending in 8
= 1x10x10x10x1 = 1000
prob(your event) = 1000/90000
= 1/90
= 9x10x10x10x10 = 90000
number starting with 7 and ending in 8
= 1x10x10x10x1 = 1000
prob(your event) = 1000/90000
= 1/90
Answered by
Anas
A 4-digit pin code can begin with any number except 0,1 & 2. If repetition of the same
digit is allowed, the probability of a pin code begin with 5 and end with a 3 is?
digit is allowed, the probability of a pin code begin with 5 and end with a 3 is?
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