Assume 5.75 uC and -2.61 uc are arranged left to right along the x axis, and that the 5.75 uC change is as x = 0.
The position X where the new charge must be located is such that
k*5.75/X^2 - k*2.61/(X-0.198)^2 = 0
Cancel out the k and solve for X, in meters.
2.61/5.75 = [(X-0.198)/X]^2
(X-0.198)/X = 0.6737 = 1 - 0.198/X
0.198/X = 0.3263
Finish it off
A 5.75 µC and a -2.61 µC charge are placed 19.8 cm apart. Where can a third charge be placed so that it experiences no net force?
1 answer