F = ma
but, friction µ reduces F, meaning that
(1-µ)F = ma
0.53F = 5.6*3.12
...
A 5.60 kg object is pulled over a rough surface with a constant tension resulting in an acceleration of 3.12 m/s2. There is a friction, and the coefficient of kinetic friction is 0.47.
What is the magnitude of the tension?
1 answer