A= ( -5,4)

B= (-1,4)

After applying a translation vector to rectangle ABDC
, the coordinates of A′
are (−6,8)
. What are the coordinates of B′
?

(1 point)
(
,
)

1 answer

To find the coordinates of \(B'\) after the translation, we first need to determine the translation vector. We know the original coordinates of point \(A\) and the new coordinates of point \(A'\):

  • Original coordinates of \(A\): \((-5, 4)\)
  • New coordinates of \(A'\): \((-6, 8)\)

The translation vector can be determined by subtracting the coordinates of \(A\) from the coordinates of \(A'\):

\[ \text{Translation vector} = A' - A = (-6, 8) - (-5, 4) = (-6 + 5, 8 - 4) = (-1, 4) \]

Now we apply this translation vector to point \(B\):

  • Original coordinates of \(B\): \((-1, 4)\)

Calculating the new coordinates of \(B'\):

\[ B' = B + \text{Translation vector} = (-1, 4) + (-1, 4) = (-1 - 1, 4 + 4) = (-2, 8) \]

Therefore, the coordinates of \(B'\) are:

\[ \boxed{(-2, 8)} \]

Similar Questions
  1. Its a rectangle the cordnates provided are A=-5,4B=—1,4 After applying a translation vector to rectangle ABDC, the coordinates
    1. answers icon 0 answers
  2. Its a rectangle the cordnates provided are A=-5,4B=—1,4 After applying a translation vector to rectangle ABDC, the coordinates
    1. answers icon 1 answer
  3. Jarvis wants to translate rectangle ABDChorizontally by −4 and vertically by +3 to produce rectangle A′B′D′C′ . What
    1. answers icon 1 answer
    1. answers icon 3 answers
more similar questions