A 5.00 kg mass is attached to a 2.00 m long pendulum near the surface of the planet Earth. Calculate the period of oscillation.

1 answer

The period of oscillation can be calculated using the formula:

T = 2π√(L/g)

Where:
T = period of oscillation
L = length of the pendulum
g = acceleration due to gravity

The acceleration due to gravity on the surface of the Earth is approximately 9.8 m/s².

Plugging in the given values:
L = 2.00 m
g = 9.8 m/s²

T = 2π√(2.00 / 9.8)
T ≈ 2π√(0.2041)
T ≈ 2π(0.452)
T ≈ 2.843 s

The period of oscillation is approximately 2.843 seconds.