A 5.00 gram sample of aluminum pellets (specific heat capacity = 0.89 J/g*C) and a 10.00 gram sample of iron pellets (specific heat capacity = 0.45 J/g*C) are heated to 100.0 *C. The mixture of hot iron and aluminum is then dropped into 97.3 gram of water at 22.0*C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

Answer 1

heat lost by Al + heat lost by Fe + heat gained by water = 0.
[mass Al x specific heat Al x (Tfinal-Tinitial)] + [mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass water x speicific heat water x (Tfinal-Tinitial)] = 0

Answer 2

24