A 5.0 kg wooden block is placed on an adjustable inclined plane. (For this problem, μs is approximately 0.55 and μk is approximately 0.25)

Question

a) What is the angle of incline above which the block will start to slide down the plane?
b) At what angle of incline will the block then slide down the plane at a constant speed?

Answer 1

a) M g sin A = M g cos A*ìs
tan A = ìs
A = 28.8 degrees

b) M g sin A = M g cosA * ìk
tan A = ìk
A = 14.0 degrees

Answer 2

Thanks