conservation of momentum:
MV+mv=MV' + mv'
10*2+5*2.8=10*2.5+5*v'
solve for v'
A 5.0 kg block with a speed of 2.8 m/s collides with a 10 kg block that has a speed of 2.0 m/s in the same direction. After the collision, the 10 kg block is observed to be traveling in the original direction with a speed of 2.5 m/s. What is the velocity of the 5.0 kg block immediately after the collision?
1 answer