4 v^2/7 = 87 *9.8
solve for v
then
Time around circle = 2 pi*7/v
A 4kg mass moves in a circular path of 7m radius on a frictionless horizontal table. It is attached to a string that passes through a frictionless hole in the center of the table. A second 87kg mass is attached to the other end of the string. Acceleration is 9.8 m/s^2. Determine the period.
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