m g = weight = 490*9.81
so potential energy gained at height h = 4806 h Joules
work in =9700 = 4806 h + (1/2)(490) (7.4)^2
A 490 kg hot-air balloon takes off from rest at the surface of the earth. The nonconservative wind and lift forces take the balloon up, doing 97000 J of work on the balloon in the process. At what height above the surface of the earth does the balloon have a speed of 7.40 m/s?
2 answers
typo
work in =97,000 = 4806 h + (1/2)(490) (7.4)^2
work in =97,000 = 4806 h + (1/2)(490) (7.4)^2
1 answer