Weight number 1:
48 + 8 + 19.5 = 75.5 kg on the wagon
19.5 kg back at 9 relative to ground and girl
so
75.5 u = 19.5 * 9
u = 2.325 forward
now
weight number 2
before throw:
momentum = 75.5 * 2.325 = 175.5
relative to ground
after throw
missile momentum back relative to ground
= 19.5 (9 -2.325 ) = 130 kg m/s back
cart and girl mass = 48+8 = 56 kg
so
56 v - 130 = momentum after
so
56 v - 130 = 175.5
56 v = 305.5
v = 5.46 meters/second
A 48-kg girl stands on a 8-kg wagon holding two 19.5-kg weights. She throws the weights horizontally off the back of the wagon at a speed of 9.0 m/s relative to herself. Assuming that the wagon was at rest initially, what is the speed with which the girl will move after she throws the weights one at a time, each with a speed of 9.0 m/s relative to herself?
1 answer