A 478.18g ice cube is taken out of the freezer at -8.5 degrees Celsius. how much heat s needed to turn it in to steam?

1 answer

q1 = heat needed to raise T from -8.5 to zero c.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial)

q2 = heat needed to melt ice at Zero C and convert to liquid H2O.
q2 = mass ice x heat fusion

q3 = heat needed to raise T of water from zero C to 100 C

q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial)_

q4 = heat needed to change liquid water at 100 C to steam at 100 C.
q4 = mass H2O x heat vaporization

Total = sum of individual qs.