q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
I would convert 349 kJ to 349,000 J and 45 kg H2O to 45,000 g and use 4.184 J/g*C for specific heat. Solve for Tf.
A 45kg sample of water absorbs 349kJ of heat. If the water was initially at 25.5 degrees Celsius, what is its final temperature?
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