A 45 m/s (100 mph) wind blows across the top of a flat-roofed house. Calculate the net force on the roof due to the pressure differential from inside the house to the outside. Assume that the pressure in the house is atmospheric pressure and that the roof has an area of 200 square meter. The density of air equals 1.3 kilogram per cubic meter.

asked by badgurl

12 years ago

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1 answer

Force = (roof area)*(1/2)*(rho)*V^2

Rho is the air density

answered by drwls

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Question

A 45 m/s (100 mph) wind blows across the top of a flat-roofed house. Calculate the net force on the roof due to the pressure differential from inside the house to the outside. Assume that the pressure in the house is atmospheric pressure and that the roof has an area of 200 square meter. The density of air equals 1.3 kilogram per cubic meter.

1 answer

Force = (roof area)*(1/2)*(rho)*V^2

Rho is the air density

drwls · Answer

Force = (roof area)*(1/2)*(rho)*V^2 Rho is the air density