To find the person's kinetic energy, we can use the formula K = 1/2 mv^2, where K is the kinetic energy, m is the mass of the person, and v is the speed of the person.
Given:
Mass of the person (m) = 45 kg
Speed of the person (v) = 12 m/s
Plugging in these values into the formula, we get:
K = 1/2 * 45 kg * (12 m/s)^2
Now, let's calculate the kinetic energy:
K = 1/2 * 45 kg * (12 m/s)^2
K = 1/2 * 45 kg * (144 m^2/s^2)
K = 0.5 * 45 kg * 144 m^2/s^2
K = 0.5 * 45 kg * 144 m^2/s^2
K = 3240 kg m^2/s^2
Therefore, the person's kinetic energy is 3240 kg m^2/s^2.
A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at
a speed of 12 mis, whatis the person's kinetic energy? Hint: Use the formula KB = 1/2 mv^2
1 answer