A 45.5-g Super Ball traveling at 29.0 m/s bounces off a brick wall and rebounds at 19.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.15 ms, what is the magnitude of the average acceleration of the ball during this time interval?
4 answers
the super ball will rebound at 0.12745 seconds at a velocity of giga 10 milliseconds.
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V1=29 , v2= -19.5 t = 4.15*10^-3
average a = (29+19.5)/4.15*10^-3
average a = (29+19.5)/4.15*10^-3