A 45.0 g golf ball is released 2.50 m above the ground. The velocity of the golf ball when it hits the ground is

Answer 1

45 g has nothing to do with this because m cancels

(1/2) m v^2 = m g h
v^2 = 2 g h
v = sqrt (2 g h) [ worth remembering ]

Answer 2

what is the answer for this questions
A 45.0 g golf ball is released 2.50 m above the ground. Calculate the the velocity of the golf ball when it hits the ground in km/h.