A 44.0kg seal at an amusement park slides from rest down a ramp into the pool below. The top of the ramp is 1.75m higher than the surface of the water and the ramp is inclined at an angle of 35.0 degrees above the horizontal.
What is the coefficient of kinetic friction between the seal and the ramp?
3 answers
This cannot be determined, without knowing more...such as the end velocity.
the end velocity is 4m/s
Ws = M*g = 44 * 9.8 = 431.2 N.
Fn = 431.2*Cos35 = 353.2 N. = Normal force
Mg*h-FE = 0.5M*V^2.
44*9.8*1.75-FE = 05*44*4^2 = 352.
-FE = 352 - 754.6 = -402.6.
FE = 402.6 J.
L = 1.75/sin35 = 3.05 m.
Fk*L = 402.6.
Fk = 402.6/L = 402.6/3.05 = 132 N.
u = Fk/Fn = 132/353.2 = 0.374.
Fn = 431.2*Cos35 = 353.2 N. = Normal force
Mg*h-FE = 0.5M*V^2.
44*9.8*1.75-FE = 05*44*4^2 = 352.
-FE = 352 - 754.6 = -402.6.
FE = 402.6 J.
L = 1.75/sin35 = 3.05 m.
Fk*L = 402.6.
Fk = 402.6/L = 402.6/3.05 = 132 N.
u = Fk/Fn = 132/353.2 = 0.374.