A 41.0 cm diameter wheel accelerates uniformly from 86.0 rpm to 342.0 rpm in 3.4 s. How far (in meters) will a point on the edge of the wheel have traveled in this time?

Answer 1

Linear speed=(RPM/60)xpixD, t=3.4s, D=0.41m
u=86x0.41x3.14/60=1.85m/s
v=342x3.41x0.41/60=7.34m/s
v=u+ft or f=(7.34-1.85)/3.4=1.61m/s^2
s=ut+ft^2/2=1.85x3.4 + 1.61x3.4^2/2 =6.29+9.31=15.60m