A 4000 kg trailer is towed up a hill with a 5% grade. If the towing truck starts from rest at the bottom of the hill and reaches a speed of 12 m/s at the top of the hill, how much is the towing force. The road from the bottom to the top of the hill is straight with a length of 200 m? Ignore friction and drag.
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Sin A = 0.05, A = 2.87o.
Fp = Mg*sin2.87 = 1963 N. = Force parallel to the incline.
V^2 = Vo^2 + 2a*d = 144.
a = 144/2d = 144/400 = 0.36 m/s^2.
F-1963 = 4000*0.36 = 1440.
F = 3403 N.
Fp = Mg*sin2.87 = 1963 N. = Force parallel to the incline.
V^2 = Vo^2 + 2a*d = 144.
a = 144/2d = 144/400 = 0.36 m/s^2.
F-1963 = 4000*0.36 = 1440.
F = 3403 N.
1 answer