Asked by Alli
A 4.65-μF and an 9.30-μF capacitor are connected in series to a 60.0-Hz generator operating with an rms voltage of 111 V. What is the rms current supplied by the generator?
The capacitors are in series so I used C = C1*C2/(C1 + C2) and got C = 3.1*10^-6
Xc = 1/wC ---> Xc = 1/(60*3.1*10^-6) = 5376
Irms = V/Xc ---> 111/5376 = .021A
But this is wrong? Thanks for the help!
The capacitors are in series so I used C = C1*C2/(C1 + C2) and got C = 3.1*10^-6
Xc = 1/wC ---> Xc = 1/(60*3.1*10^-6) = 5376
Irms = V/Xc ---> 111/5376 = .021A
But this is wrong? Thanks for the help!
Answers
Answered by
bobpursley
w=2PI*f
Xc=1/(2PI*f*C)
Xc=1/(2PI*f*C)
Answered by
Alli
Thanks for your help! I see my mistake!
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