A 4.6 kg object is subjected to two forces,

Question

F~1 = (2.8 N)iˆ+(−3.5 N)jˆ and
F~2 = (4 N)iˆ+(−11.5 N)jˆ. The object is at rest at the origin at time t = 0.What is the magnitude of the objects acceleration?
-i've tried using the equation netforce=M*A but have had no success.

Answer 1

x direction
Fx = 2.8 + 4 = 6.8
Fy = -3.5 - 11.5 = - 15

Ax = 6.8/4.6
Ay = -15/4.6

|A| = sqrt (Ax^2 + Ay^2)