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a 4.5kw electric motor is 90% efficient.how much energy it use in 20 seconds.

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12 minutes

13 minutes

E=Pt/η=4500•20/0.9=100000 J =0.1 MJ

100KJ

90kj

4.5kW = 90%
5.0kW = 100%

W= 5000W x 20
= 100000J @ 100kJ

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