Asked by ryan

A 4.50 kg block is pressed against a vertical wall by a force (→F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.34 and the directional angle θ for the force is 48.0°. Determine the magnitude of the force (→F) when the block is about to slide down the wall.

Figure:
imgur. com/a/cFWYLRj

The two answers I got so far which are wrong are:
105.8921754
45.43350838

I will continue trying to do this question but I only have one submission attempt left
Answered by bobpursley
assuming the force is upward (the angle below the horizontal), I dont have the picture
forceup=sinTheta*F=F*sin48
force normal= F
force up due to friction= F*mu=F*.34
force down due to gravity=4.5*9.8=44.1
so if they are all balanced, then forcup=forcedown or
F*sin48+F*.34=44.1
F= 44.1/(.743 +.34)=40.7 or in sig digits 41N
Now if the force pressing is above the horizontal, that changes the equation.
Answered by ryan
delete the space in the imgur link to get the picture
Answered by trying
Where did .743 come from?
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