assuming the force is upward (the angle below the horizontal), I dont have the picture
forceup=sinTheta*F=F*sin48
force normal= F
force up due to friction= F*mu=F*.34
force down due to gravity=4.5*9.8=44.1
so if they are all balanced, then forcup=forcedown or
F*sin48+F*.34=44.1
F= 44.1/(.743 +.34)=40.7 or in sig digits 41N
Now if the force pressing is above the horizontal, that changes the equation.
A 4.50 kg block is pressed against a vertical wall by a force (→F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.34 and the directional angle θ for the force is 48.0°. Determine the magnitude of the force (→F) when the block is about to slide down the wall.
Figure:
imgur. com/a/cFWYLRj
The two answers I got so far which are wrong are:
105.8921754
45.43350838
I will continue trying to do this question but I only have one submission attempt left
3 answers
delete the space in the imgur link to get the picture
Where did .743 come from?
1 answer