A 4.0 kg pulley of radius 0.15 m is pivoted about an axis through its center. What constant torque is required for the pulley to reach an angular speed of 25 rad/s after rotating 6.0 revolutions, starting from rest?

Answer 1

Torque=momentinertia*anglular acceleration

Torque= I * angacc

but

wf^2=wi^2+2*angacc*displacement

wf^2=wi^2+2*angacc*revolutions*2PI

where w is in rad/sec, angacc in rad/sec^2

solve for angacc, then torque