m₁=0.004 kg, v₁₀=0.26 m/s
m₂=0.012 g, v₂= -0.13 m/s
v₁=?
m₁v₁₀ = m₁v₁ +m₂v₂
v₁= (m₁-m₂)v₁₀/(m₁+m₂)
ΔKE = m₁v₁₀²/2- m₁v₁²/2=
=m ₂v₂²/2= …
A 4.0 g coin sliding to the right at 26.0 cm/s makes an elastic head-on collision with a 12.0 g coin that is initially at rest. After the collision, the 4.0 g coin moves to the left at 13 cm/s.
(a) Find the final velocity of the other coin.
cm/s
(b) Find the amount of kinetic energy transferred to the 12.0 g coin.
J
1 answer