The charges attract each other, so the force on the positive charge is to the left. Use Coulomb's law for the magnitude.
F = k q1*q2/R^2
A -4.0-µC charge is located 0.30 m to the left of a +6.0-µC charge. What is the magnitude and direction of the electrostatic force on the positive charge?
3 answers
10
F = k q1*q2/R^2
F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)
F = 2.4 N to the left
F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)
F = 2.4 N to the left
1 answer