The speed of the ball when it is 0.25 m high can be calculated using the equation for kinetic energy: KE = 1/2 mv^2.
KE = 1/2 (375 g)(3.0 m/s)^2 = 5.625 J
KE = 1/2 (375 g)(v^2)
v = sqrt(11.25 J/375 g) = 2.5 m/s
Therefore, the speed of the ball when it is 0.25 m high is 2.5 m/s.
A 375 g ball is thrown vertically upward with a speed of 3.0 m/s. How high did it go? How fast is it moving when it is 0.25 m high?
How fast is it moving when it is 0.25 m high?
1 answer