A 37 ohm lamp and a 59 ohm lamp are connected in series and placed across a potential of 43 V.
What is the equivalent resistance of the
circuit?
What is the current in the circuit?
Answer in units of A.
What is the voltage drop across the first
lamp?
Answer in units of V.
What is the power dissipated in the first
lamp?
Answer in units of W.
3 answers
I will be happy to critique your thinking on this.
I was only able to get the first and second question. Not the last two.
Req. = R1+R2 = 37 + 59 = 96 Ohms.
I = E/Req. = 43/96 = 0.448A
V1 = I*R1 = 0.448 * 37 = 16.6 Volts.
P1 = V1*I = 16.6 * 0.448 = 7.44 W.
I = E/Req. = 43/96 = 0.448A
V1 = I*R1 = 0.448 * 37 = 16.6 Volts.
P1 = V1*I = 16.6 * 0.448 = 7.44 W.
1 answer