A 35-kg trunk is dragged 10 m up a ramp inclined at an angle of 12º to the
horizontal by a force of 90 N applied at an angle of 20º to the ramp. At the
top of the ramp, the trunk is dragged horizontally another 15 m by the same
force. Find the total work done.
My attempt: (10)(34)cos(70) = 1173J
Textbook answer: 2114J
2 answers
what about the work dragging it horizontally? again, force * distance
Ehhhhh kind of late response but I just had to figure this out for my class and I was over it but it turns out the 12 degrees is just irrelevant in this context. The question is just really poorly worded so I wouldn't worry about it too much. The formula to solve is as follows:
(90)(10)cos(20) + (90)(15)cos(20) = 2114 J
(90)(10)cos(20) + (90)(15)cos(20) = 2114 J
3 answers