A 35.0 g block of copper at 350.0 degrees celcius is added to a beaker containing 525 g of water at 35.0 degrees celcius. What is the final temperature of water?

Answer 1

heat lost by Cu + heat gained by H2O = 0
[mass Cu x specific heat Cu x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Substitute and solve for Tf.