Ask a New Question
Menu

A 34-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 480 J. How high does she rise during this interval? Neglect air resistance.

1 answer

KE + PE = 480 Joules
220 + PE = 480
PE = PE = 260 J.
mg*h = 260
34*9.8*h = 260
333.2h = 260
h = 0.780 m.
Similar Questions
  1. Use g=10 N/kg in this assignment.1. What is the gravitational energy (relative to the unstretched surface of the trampoline) of
    1. answers icon 1 answer
  2. Use g=10 N/kg in this assignment.1. What is the gravitational energy (relative to the unstretched surface of the trampoline) of
    1. answers icon 2 answers
    1. answers icon 3 answers
    1. answers icon 9 answers
more similar questions