well, it is wrong, you know the final answer is between 21.6 and 38.7C
Let me see your calculations, including what you used as specific heats of glass and water.
A 34 g glass thermometer reads 21.6°C before it is placed in 135 mL of water. When the water and thermometer come to equilibrium, the thermometer reads 38.7°C. What was the original temperature of the water?
I need help on this please could someone please help out.Thank you!
Physics - bobpursley, Tuesday, April 24, 2012 at 5:53pm
the sum of heats gained is zero.
massglass*specheatglass*(21.6-38.7)+135*specheatwater*(Ti-38.6)=0
solve for Ti
Physics - Akbar, Tuesday, April 24, 2012 at 6:58pm
I got 15.43 degree Celsius but its wrong. I don't know why please help. Thank you!
2 answers
This is how I did it:
(.034)(840)(21.6-38.7)+135(4186)(Ti-38.6)
(.034)(840)(21.6-38.7)+135(4186)(Ti-38.6)