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A 3300kg satellite is traveling 3550 km above the Earth's surface. Calculate the velocity and period of the satellite. THANK YO...Asked by Mike Jones
A 3300kg satellite is traveling 3550 km above the Earth's surface. Calculate the velocity and period of the satellite.
THANK YOU VERY MUCH!!!!
THANK YOU VERY MUCH!!!!
Answers
Answered by
drwls
The satellite's mass doesn't matter.
You will need to use the fact that the Earth's radius is 6371 km. The satellite is therefore 9921 km from the Earth's center. The value of the acceleration of gravity (g') there is
g' = g*(6371/9921)^2 = 4.046 m/s^2
where g = 9.81 m/s^2 is the value of the acceleration at the Earth's surface.
You can get the velocity V by using
V^2/R = g'
V = 6335 m/s
The period P of the satellite is given by
V*P = 2*pi*R
P = 9840 s = 2.73 hours
You will need to use the fact that the Earth's radius is 6371 km. The satellite is therefore 9921 km from the Earth's center. The value of the acceleration of gravity (g') there is
g' = g*(6371/9921)^2 = 4.046 m/s^2
where g = 9.81 m/s^2 is the value of the acceleration at the Earth's surface.
You can get the velocity V by using
V^2/R = g'
V = 6335 m/s
The period P of the satellite is given by
V*P = 2*pi*R
P = 9840 s = 2.73 hours
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