A 31.9 g silver spoon at 18.3°C is placed in a cup of coffee at 88.0°C. A short time later, the spoon is at 83.5°C. If, during this same time, the temperature of the coffee has fallen by 0.8°C, what is the mass of the coffee? (csilver = 0.056 cal/g°C and assume ccoffee = 1.0 cal/g°C)
1 answer
31.9 * (83.5 - 18.3) * 0.056 = m * 0.8 ... grams