A 300g particle oscillating in SHM travels 11cm between the two extreme points in its motion with an average speed of 65 cm/s.

Question

a) Find the angular frequency
b)The maximum force on the particle
c)The maximum speed

Answer 1

a. period=11/65 seconds
angular freq=2PI/period=w

b. force=mass*acceleration

I assume you know a little calculus. Amplitude is 11/2
displacement=amplitude*sin(ang freq *time)

taking the derivative, w=angfreq
velocity= wA*cos(wt)
taking the second derivative
acceleration=-Aw^2sin(wt)
max acceleration=-A w^2
max force= mass*maxacceleration

max velocity (above) when cosine is 1, so vmax=wA