A 300g lead is heated to 95celsius and is then dropped into 100g of water at 10celsius. If the final temperature is 15celsius. What is the specific heat of the lead?
2 answers
A 500g copper at 100celsius is placed in a 200g water at 25celsius which is contained in an aluminum calorimeter that has a mass of 400g. If the final temperature of the whole system is 30celsius, find the specific heat of the lead.
The sum of heats GAINED is zero.
heat Gained=mass*specificeheat*(Tf-Ti)
Heatgainedby water + heatgained by lead=0
Mwater*specifhtWater*(Tf-ti)+Masslead*specihtLead*(Tf-Ti)=0
solve.
heat Gained=mass*specificeheat*(Tf-Ti)
Heatgainedby water + heatgained by lead=0
Mwater*specifhtWater*(Tf-ti)+Masslead*specihtLead*(Tf-Ti)=0
solve.
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