q(loss of Fe) = - q(gain of water)
q= m*specific heat * delta T(which is Tf-Ti)
Note: convert your units first.
A 30 ounce iron bar at 425 degrees Fahrenheit is placed in 2.00 quarts of water at 80.0 degrees Fahrenheit. What will be the change in temperature of the iron bar in degrees Fahrenheit?
(Assume 1/3 heat lost to the surroundings)
Specific heat of iron= .473 Joules/grams degrees Celcius.
1 answer
1 answer