A 30 g sample of water at 280 K is mixed with 50 g water at 330 K. Calculate the final temperature of the mixture assuming no heat loss to the surroundings.

Answer 1

let C = specific heat of water
heat gained = C*30*(T-280)
heat lost = C * 50(330-T)
so
30(T-280) = 50 (330-T)