The equation of the unit circle is given by:
\[ x^2 + y^2 = 1 \]
In this case, we know \( y = 12 \). We can substitute \( y \) into the equation:
\[ x^2 + 12^2 = 1 \]
Calculating \( 12^2 \):
\[ x^2 + 144 = 1 \]
Now, we can isolate \( x^2 \):
\[ x^2 = 1 - 144 \] \[ x^2 = -143 \]
Since \( x^2 \) cannot be negative, this indicates that there are no real values of \( x \) corresponding to the point on the unit circle with \( y = 12 \). Therefore, the point \( (x, 12) \) does not intersect the unit circle.
The value of \( x \) cannot be determined as part of a point on the unit circle.