All of the stored potential energy of the spring, (1/2)kX^2, winds up as heat. X is the spring compression, which they don't tell you.
You can compute the heat generated another way:
Friction work = M*g*Uk*X = 66.9 J
a 3.5 kg block is accelerated from rest by a compressed spring of spring constant 640 N/m. The block leaves the spring at the springs relaxation length.The block then travels over a horizontal floor with coefficient of kinetic friction 0.25. The friction force stops the block in a distance D = 7.8 m.
What is the increase in the thermal energy of the block+floor system?
4 answers
What is the original compression distance of the spring?
Thought it would be zero but that isn't right.
Thought it would be zero but that isn't right.
You can calculate the spring compression X from
66.9 J = (1/2)kX^2, but you don't need it. 66.9 J is the thermal energy increease.
They gave you more information than you need to answer the question
66.9 J = (1/2)kX^2, but you don't need it. 66.9 J is the thermal energy increease.
They gave you more information than you need to answer the question
(a) W=F*X
W= u*Fn*X
=>M*g*uk*X -> 4.3kg*0.26*7.8m
(b) same as (a)
(c) Us=0.5*k*x^2
=> (a)=0.5*640N/m*x^2
figure out X from that
[very late but someone might benefit from this]
W= u*Fn*X
=>M*g*uk*X -> 4.3kg*0.26*7.8m
(b) same as (a)
(c) Us=0.5*k*x^2
=> (a)=0.5*640N/m*x^2
figure out X from that
[very late but someone might benefit from this]