A 3.44 L expandable container is heated until its temperature increases from 0.0 ºC to 70 ºC. What is the new volume if the pressure remains constant?

Answer 1

To find the new volume of the expandable container, we can use the equation for thermal expansion:

V2 = V1 * (1 + α * ΔT)

Where:
V1 = initial volume of the container = 3.44 L
α = coefficient of volume expansion for the material of the container
ΔT = change in temperature = 70 ºC - 0.0 ºC = 70 ºC

Since the pressure remains constant, the volumetric thermal expansion coefficient α can be considered constant.

Assuming a typical value for the coefficient of volume expansion of a solid material, we can use α = 3 × 10^-5 K^-1.

Plugging in the values:

V2 = 3.44 L * (1 + 3 × 10^-5 K^-1 * 70 ºC)
V2 = 3.44 L * (1 + 0.0021)
V2 = 3.44 L * 1.0021
V2 = 3.45 L

Therefore, the new volume of the expandable container after heating it to 70 ºC is 3.45 L.