A 3.3-kg ball of clay with a speed of 14 m/s is thrown against a wall and sticks to the wall. What is the magnitude of the impulse exerted on the ball?

Answer 1

It is the product of those two numbers: the momentum change.

Answer 2

initial momentum= mass x velocity
= 3.3 x 14
= 46.2 Ns (to the wall)
final velocity= 0 therfore final momentum = 0

change in momentum = final momentum- initial momentum
= 0 - 46.2 (to the wall)
= 46.2 (away from the wall)
Impulse= change in momentum
= 46.2 Ns (away from the wall)