I guess it is at constant velocity
m g = 3.1*9.81 = 30.4 N weight
mu m g = 43.5 N
mu = 43.5/30.4 = 1.43
A 3.10 kg block is pushed along a floor by a constant applied force that is horizontal and has a magnitude of 43.5 N. What is the coefficient of kinetic friction between the block and the floor?
I tried dividing the N by the KG and vise versa but it didn't work
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