a 3.0L helium balloon is placed in a car sitting in hot sunlight. The temperature in the mall, when the balloon was bought, was 22C. The temperature in the car is 45C.
what will be the new volume of the of the balloon.
Will it be: 6.14L?
I would think this looks right but the only thing that confuses me, is that I think the volume should actually decrease, not increase.
Please Help
Thanks
4 answers
Why should it decrease. Charles' Law says that volume increases if T increases. T went from 22 to 45. That's an increase and V should increase. The only think you have done wrong is to use degrees C for temperature. Charles' Law works only for KELVIN.
but is my answer correct?
How can it be correct if you used C instead of Kelvin?
V1/T1= V2/T2
V1 = 3.0 L
V2 = solve for this
T1 = 22 + 273
T2 = 45 + 273
V1/T1= V2/T2
V1 = 3.0 L
V2 = solve for this
T1 = 22 + 273
T2 = 45 + 273
2+2=?
2 answers