To find the number of grams of ammonia in the flask, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure (in atm)
V = volume (in L)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in K)
First, we need to convert the temperature from Celsius to Kelvin:
T = 20.0 + 273.15
T = 293.15 K
Now we can rearrange the ideal gas law equation to solve for the number of moles of ammonia:
n = PV / RT
n = (2.05 atm)(3.00 L) / (0.0821 L·atm/mol·K)(293.15 K)
n = 0.250 moles
To find the mass of ammonia in grams, we can use the molar mass of ammonia (NH3), which is 17.03 g/mol:
mass = number of moles * molar mass
mass = 0.250 moles * 17.03 g/mol
mass = 4.26 grams
Therefore, there are 4.26 grams of ammonia in the flask.
A 3.00- L
flask is filled with gaseous ammonia, NH3
. The gas pressure measured at 20.0 ∘C
is 2.05 atm
. Assuming ideal gas behavior, how many grams of ammonia are in the flask?
1 answer