A 3.00 kHz tone is being produced by a speaker with a diameter of 0.175 m. The air temperature changes from 0 to 29°C. Assuming air to be an ideal gas, find the change in the diffraction angle
My solution
v directly proportional to sqrt T
v = sqrt 302 =17.382
lambda = v/f = 17.382/3000
=0.005794
Sin theta = 1.22 lambda/ diameter
= 1.22x 0.005794/0.175
=0.009425
theta = Sin^-1 0.009425
= 0.54
answer is wrong
First, v is prop to sqrt T does NOT mean that v=sqrt(Temp). That is plain wrong. So lambda that follows is wrong, and the angle also.
http://www.sengpielaudio.com/calculator-speedsound.htm
I used the calculator but stll got the wrong answer. PLease show work
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